217.Contains Duplicate
LeetCode 217. Contains Duplicate [Easy]
- Given an integer array
nums
, returntrue
if any value appears at least twice in the array, and returnfalse
if every element is distinct.
Input: nums = [1,2,3,1]
Output: true
Example 2
Input: nums = [1,2,3,4]
Output: false
Example 3
Input: nums = [1,1,1,3,3,4,3,2,4,2]
Output: true
Method 1
【O(n)time∣O(n)space】
package Leetcode.Array;
import java.util.HashSet;
import java.util.Set;
/**
* @author zhengstars
* @date 2024/02/19
*/
public class ContainsDuplicate {
public static boolean containsDuplicate(int[] nums) {
// Create a new HashSet instance
Set<Integer> set = new HashSet<Integer>();
// Iterate over the given array
for (int x : nums) {
// Try to add each element to the set
if (!set.add(x)) {
// If set.add() returns false, it means the element already exists in the set (duplicate found)
return true;
}
}
// If no duplicate is found after the iteration, return false
return false;
}
/**
* The main function to test the solution
*/
public static void main(String[] args) {
// Test case 1. Expected output: true
int[] nums1 = {1,2,3,1};
System.out.println(containsDuplicate(nums1));
// Test case 2. Expected output: false
int[] nums2 = {1,2,3,4};
System.out.println(containsDuplicate(nums2));
// Test case 3. Expected output: true
int[] nums3 = {1,1,1,3,3,4,3,2,4,2};
System.out.println(containsDuplicate(nums3));
}
}
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