58. Length of Last Word
- Given a string
sconsisting of words and spaces, return the length of the last word in the string. - A word is a maximal substring consisting of non-space characters only.
Example 1
Input: s = "Hello World"
Output: 5
Explanation: The last word is "World" with length 5.
Example 2
Input: s = " fly me to the moon "
Output: 4
Explanation: The last word is "moon" with length 4.
Example 3
Input: s = "luffy is still joyboy"
Output: 6
Explanation: The last word is "joyboy" with length 6.
Method 1
【O(n) time | O(1) space】
package Leetcode.String;
/**
* @author zhengxingxing
* @date 2024/12/07
*/
public class LengthOfLastWord {
public static int lengthOfLastWord(String s) {
int length = 0;
for (int i = s.length() - 1; i >= 0; i--) {
if(s.charAt(i) != ' '){
length++;
}else if(length > 0){
break;
}
}
return length;
}
public static void main(String[] args) {
// Test case 1: Normal string with single space
String test1 = "Hello World";
System.out.println("Test 1: \"" + test1 + "\"");
System.out.println("Length of last word: " + lengthOfLastWord(test1));
// Test case 2: String with trailing spaces
String test2 = " fly me to the moon ";
System.out.println("\nTest 2: \"" + test2 + "\"");
System.out.println("Length of last word: " + lengthOfLastWord(test2));
// Test case 3: Single word
String test3 = "luffy";
System.out.println("\nTest 3: \"" + test3 + "\"");
System.out.println("Length of last word: " + lengthOfLastWord(test3));
// Test case 4: Empty string
String test4 = "";
System.out.println("\nTest 4: \"" + test4 + "\"");
System.out.println("Length of last word: " + lengthOfLastWord(test4));
}
}
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