21.Merging Linked Lists
LeetCode 21. Merging Linked Lists
-
You are given the heads of two sorted linked lists
list1
andlist2
. -
Merge the two lists in a one sorted list. The list should be made by splicing together the nodes of the first two lists.
-
Return the head of the merged linked list.
**Example 1: **
Input: list1 = [1,2,4], list2 = [1,3,4]
Output: [1,1,2,3,4,4]
**Example 2: **
Input: list1 = [], list2 = []
Output: []
**Example 3: **
Input: list1 = [], list2 = [0]
Output: [0]
Method 1
【O(n + m)time∣O(1)space】
package LinkedLists;
/**
* @author zhengstars
* @date 2023/06/16
*/
public class MergingLinkedLists {
public static class ListNode {
int val;
ListNode next;
ListNode(int val) {
this.val = val;
}
}
public static ListNode mergeTwoLists(ListNode list1, ListNode list2) {
// Create the head node of the merged list
ListNode mergedHead = new ListNode(0);
// Current node pointer
ListNode current = mergedHead;
ListNode p1 = list1;
ListNode p2 = list2;
while (p1 != null && p2 != null) {
if (p1.val <= p2.val) {
// Add p1 node to mergedHead
current.next = p1;
// Move p1 pointer
p1 = p1.next;
} else {
// Add p2 node to mergedHead
current.next = p2;
// Move p2 pointer
p2 = p2.next;
}
// Move current node pointer
current = current.next;
}
// Add the remaining part to the end of mergedHead
if (p1 != null) {
current.next = p1;
}
if (p2 != null) {
current.next = p2;
}
// Return the head node of the merged list
return mergedHead.next;
}
public static void main(String[] args) {
// list1: 1 -> 2 -> 4
ListNode node1 = new ListNode(1);
ListNode node2 = new ListNode(2);
ListNode node4 = new ListNode(4);
node1.next = node2;
node2.next = node4;
// list2: 1 -> 3 -> 4
ListNode node1_2 = new ListNode(1);
ListNode node3 = new ListNode(3);
ListNode node4_2 = new ListNode(4);
node1_2.next = node3;
node3.next = node4_2;
ListNode mergedList = mergeTwoLists(node1, node1_2);
while (mergedList != null) {
System.out.print(mergedList.val + " ");
mergedList = mergedList.next;
}
}
}
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