2278. Percentage of Letter in String
- Given a string
sand a characterletter, return the percentage of characters insthat equalletterrounded down to the nearest whole percent.
Example 1
Input: s = "foobar", letter = "o"
Output: 33
Explanation:
The percentage of characters in s that equal the letter 'o' is 2 / 6 * 100% = 33% when rounded down, so we return 33.
Example 2
Input: s = "jjjj", letter = "k"
Output: 0
Explanation:
The percentage of characters in s that equal the letter 'k' is 0%, so we return 0.
Method 1
【O(n) time | O(1) space】
package Leetcode.String;
/**
* @author zhengxingxing
* @date 2025/03/31
*/
public class PercentageOfLetterInString {
public static int percentageLetter(String s, char letter) {
// Initialize counter to track letter occurrences
int count = 0;
// Iterate through each character in the string
for (char c : s.toCharArray()) {
// Increment counter when matching letter is found
if (c == letter) {
count++;
}
}
// Calculate and return the percentage rounded down
return (count * 100) / s.length();
}
public static void main(String[] args) {
// Test Case 1: String with multiple occurrences of target letter
String s1 = "foobar";
char letter1 = 'o';
System.out.println("Test Case 1 Result: " + percentageLetter(s1, letter1)); // Expected output: 33
// Test Case 2: String without any occurrence of target letter
String s2 = "jjjj";
char letter2 = 'k';
System.out.println("Test Case 2 Result: " + percentageLetter(s2, letter2)); // Expected output: 0
// Test Case 3: Additional test case with target letter 'e'
String s3 = "percentage";
char letter3 = 'e';
System.out.println("Test Case 3 Result: " + percentageLetter(s3, letter3)); // Expected output: 30
}
}
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